Question

*4. Five boys Alan, Ben, Chris, Den and Eng
share a sum of money.
1/5
Alan takes
of the sum of money.

After Alan has taken his share, Ben takes
1/3
of the remaining money.
After Ben has taken his share, Chris takes
1/4
of the remaining money.
After Chris has taken his share, Den takes
1/7
of the remaining money.
After Den has taken his share, Eng takes all
the remaining money.
What fraction of the sum of money is Eng's
share?​

Answer 1

Answer:

12/35

Step-by-step explanation:

Let's use T for the total amount of money.

After Alan takes (1/5)*T, the amount remaining is T - (1/5)*T = (4/5)*T

After Ben takes his (1/3)*(remaining) = (1/3)*(4/5)*T, there is (2/3)*(4/5)*T remaining

Then Chris takes (1/4)*(remaining), leaving (3/4)*(2/3)*(4/5)*T

And, Den takes (1/7)*(remaining), leaving (6/7)*(3/4)*(2/3)*4/5)*T for Eng

Now, cancel out numbers to get (12/35)*T

The fraction that Eng gets is 12/35

Answer 2

Answer:

Let the total sum of money be y,

 Alan takes = 1/5 y

Now, the amount remaining is = y - 1/5y

                                                      =  4/5y

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After that Ben takes the remaining of money:

        1/3 X 4/5y = 4/15 y,

  therefore the remaining is: 2/3 X 4/5Xy = 8/15y,

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Then Chris took:

     1/4 x 8/15y = 2/15y

therefore the remaining is :

          3/4 X 8/15y = 2/5y

-------------------------------------------------------------

and Den took:

     1/7 x 2/5y = 1/10y .

therefore the remaining is:

6/7 x 2/5y = 12/35.

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Therefore the fraction of money Eng receivies is 12/35.

Step-by-step explanation: