Question

4. Flo and Carl each must read a 500-page book. Flo reads one page every minute.
Carl reads one page every 50 seconds. Flo starts reading at 1:00, and Carl starts
reading at 1:30. When will Carl catch up to Flo?​

Answer 1

$\LARGE{\bf{\underline{\underline{GIVEN:-}}}}$

• Flo and carl must read a 500 page book.
• Flo reads one page every 1 minute (60 seconds).
• Carl reads one page every 50 Seconds.
• Flo starts reading at 1:00.
• Carl starts reading at 1:30.

Uff, this info seems confusing, but it is easy.

$\LARGE{\bf{\underline{\underline{TO \ FIND:-}}}}$

When will carl catch up to flo?

$\LARGE{\bf{\underline{\underline{SOLUTION:-}}}}$

There are various ways to solve this but I will attempt it using rate method.

Let Flo read certain pages when carl catches up with him. Then carl also read the same amount pages at that time.

Let the time passed be "x" minutes.

If carl Reads 1 page every 50 seconds, then 50 seconds can be written as 5/6th of a minute.

Carl's rate will be:

$\sf Rate_{carl}=\dfrac{Pages}{minutes} =\dfrac{1}{\dfrac{5}{6} } =\dfrac{6}{5}$

Now, flo got a 30 minute head start. therefore, when carl catches up, he will read certain pages at x + 30 minutes.

And the number of pages that carl read after the time he had started, that is, "x" minutes will be:

$\to \sf \dfrac{6}{5} \times x$

But, the number of pages carl and flo read will be the same at that time!

$\red \therefore \sf \dfrac{6x}{5} =x+30$

$\to \sf \dfrac{6x}{5} -x=30$

$\to \sf \dfrac{x}{5} =30$

$\to \sf x=(30 \times 5) \ minutes$

$\to \sf{\red{x=(150) \ minutes}}$

So carl catches up after 150 minutes. Now, 1:30 + 150 minutes = 1.5 hours + 2.5 hours = 4:00.

Carl will catch up at 4:00.

Regards,

SujalSirimilla

Ex-brainly star.

Answer 2

$\underline{\orange{\bf Given :-}}$

• Flo reads one page every minute
• Carls reads one page every 50 seconds
• Carl stars 30 minutes late
• Max number of pages = 500

$\underline{\orange{\bf To \: Find :-}}$

• When will Carl catch up to Flo ?

$\underline{\orange{\bf Solution :-}}$

☆ Let ☆

• x be the number of pages each reads when Carl cathes up Flo

☆ Then ☆

• We have the time for Flo and Carl

Flo : x pages after x minutes

Carl : x pages after 30 + x*50/60 minutes

$\underline{\orange{\bf A.T.Q :-}}$

$\implies$x = 30 + 50/60x

$\implies$x = 30 + 5/6x

$\implies$x - 5/6x = 30

$\implies$1/6x = 30

$\implies$x = 6*30

$\implies$x = 180

☆ We know that ☆

• 180 minutes = 3 hours

☆ Then ☆

• 1:00 + 3 hours = 4:00

∴ Carl will catch up Flo at 4:00