Question

4) For a G.P.
ii) If ty=16, t;=512 , find S.​

Answer 1

Answer:

Tu=ar³=16————(1)

T9=ar^8=512————(2)

equating (1) and (2)

16/r³=512/r^8

r^5=512/16

r^5=32

r^5 (2)^5

therefore, r=2————(3)

and a=16/(2)³

therefore, a=16/8=2————(4)

Sn=a(1-r^n)/(1-r)

solution=a(1-(2)^10/(1-2)————(from 3)

=2(1-1024)/(-1)————(from 4)

=2(1023)

=2046 is the answer

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Answer 2

Step-by-step explanation:

sorry I can understand