Question

4) For an A.P, if a = 10 and d = 3, find tn.​

Answer 1

Answer:

tn= a+(n-1)d

tn = 10+(n-1)3

tn =10+3n-3

tn =7+3n

Answer 2

Answer:

tn= 3n+ 7

Step-by-step explanation:

• A.P. means arithmetic progression.
• Arithmetic progression is the sequence of the numbers in which there is a fixed different between the number and its successive number.
• If a1, a2,a3,.. are in A P. and d is the difference between the two consecutive numbers, then the nth term can be written as

$tn = a + (n - 1) \times d$

where, a =a1 =first term

n= nth number

d= common difference between two consecutive numbers.

In the question, it is given that

$d = 3$

$a = 10$

$tn = a + (n - 1) \times d$

putting the values of a and d , we get

$tn = 10 + (n - 1) \times 3$

$tn = \: 10 + 3n - 3$

$tn = 7 + 3n$

If we know the value of n, then tn can be calculated.

Conclusion: The value of tn is 3n+7

For more information about AP following links are provided:

https://brainly.in/question/27318978?r

https://brainly.in/question/20102868?