Question

4. For an A.P. if S10 = 150 and S9 = 126, find t9.
E​

Answer 1

Answer:

Yar brainlist banado:)

Answer

REQUEST:)  Follow Me

happy Diwali

Answer 2

Step-by-step explanation:

S10 = n/2[2a + (n-1)d] = 5[2a + 9d]

= 10a + 45d = 150 --------->(1)

S9 = (9/2)[2a+8d] .

9[2a+8d] = 126×2

18a + 72d = 252.----->(2)

[(1)×18] – [(2)×10].

180a + 810d = 2700.

– (180a + 720d = 2520)

On solving above 2 equations,We get:-

d = 2. and a = 6.

tn= a + (n-1)d.

t9 = 6 + 8(2).

t9 = 22.