Question

4. For set A = {4, 10, x, 12, y, 20), all the elements are positive integers greater than or equal
to 4. Also, x<y and x, y < 10 and the median of set A is 8. The value of x is 4.
A. Always
B. Sometimes
C.never​

Answer 1

Given set A = {4, 10, x, 12, y, 20),

all the elements are positive integers greater than or equal

all the elements are positive integers greater than or equalto 4.

Also, x<y and x, y < 10 and the median of set A is 8. The value of x is 4.

/* According to the problem

Arranging the data in ascending order , we get */

$A = \{ 4,x,y,10,12,20 \}$

$Number \: of \: elements \: in \:set \: A (n) = 6$

$\blue {( even )}$

$Median\: of \: the \:data = 8$

$Average \:of \: \frac{n}{2} \: and \:\Big( \frac{n}{2}+1 \Big) ^{th} \: terms= 8$

$\implies Average \:of \: \frac{6}{2} \: and \:\Big( \frac{6}{2}+1 \Big) ^{th} \: terms= 8$

$\implies Average \:of \: 3^{rd}\: and \: 4^{th} \: terms= 8$

$\implies \frac{y+10}{2} = 8$

$\implies y + 10 = 16$

$\implies x = 16 - 10$

$\implies \green{ y = 6 }$

$\therefore \blue { The \: value \: of \: x \: is \: sometimes \: 4 }$

$Option \: \pink { ( B ) } \:is \: correct.$

•••♪

Answer 2

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