4) For the following reactions, identify the atom(s) being oxidized and reduced: (a). 2 Al(s) + 3Cl2(g) — 2AlCl3(s) (b). C(s) + 2Cl2(g) → CC14(1)
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Answer:
OXIDISED: AL
REDUCED CL2
Explanation:
THE OXIDATION STATE OF AL IN REACTANT SIDE IS 0 AND IN THE PRODUCT SIDE IS 3/2 SO IT IS OXIDISED AND CHLORINE IS REDUCED
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