Question

4. For the reaction 2A + B → 2C, doubling the concentration of B doubles the rate and doubling the concentration of A
also doubles the rate. The rate law is
(a) rate = k[A]”[B] (b) rate = k[A][B] (c) rate = k[A]”[B][C] (d) rate = k[A]”[B]
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Answer 1

Rate = k[A][B] b) Rate = k[A]+[B] Rate = k[A][B] d) Rate = k[A]?[B]. 17-1. 2. ... doubled for the reaction, there is no change in the reaction rate. ... For the reaction AB → A + B, concentration of AB was measured as the For the reaction 2A + B → 2C, doubling the concentration of B doubles the rate and doubling the concentration of A

also doubles the rate. The rate law is

(a) rate = k[A]”[B] (b) rate = k[A][B] (c) rate = k[A]”[B][C] (d) rate = k[A]”[B]

किसने किससे कहा,

1. चलो मैं भी चल कर देखता हूँ,

2आओ उठो हमें भीमा का हाथ बटाना चाहिए

3. क्या वक्ता है । class 8(1) Dhoni dropped the ball.

(Who)

(2) The policeman stopped me. (Who)

Answer 2

Explanation:

Q)4. For the reaction 2A + B → 2C, doubling the concentration of B doubles the rate and doubling the concentration of A

also doubles the rate. The rate law is

(a) rate = k[A]”[B] (b) rate = k[A][B] (c) rate = k[A]”[B][C] (d) rate = k[A]”[B].

Answer -refer to the attachment