Question

4) For what value of p are 2p + 1, 13, 5p – 3, three consecutive terms of an AP?

Answer 1

Answer:

p=4

Step-by-step explanation:

b=13

a=2p+1

c=5p-1

For three consecutive no.s in an AP

b=(a+c)/2

therefore,

13=(2p+1+5p-3)/2

26=7p-2

28=7p

4=p

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