Math, asked by lisa316, 9 months ago

4.) From three 5- digit number the are each in
1 .divisible by 3 but not 9
2.divisible by both 9 and 5
3.not divisible by 4 and 3
4.divisible by both 5 and 8​

Answers

Answered by motilalchoudhary10
0

Answer:

(A) a + 2b = 3ab

(C) a - 2b = 3ab

(B) 1 + 2ab = 3b

(D) 3b + 1 = 2ab(A) a + 2b = 3ab

(C) a - 2b = 3ab

(B) 1 + 2ab = 3b

(D) 3b + 1 = 2ab(A) a + 2b = 3ab

(C) a - 2b = 3ab

(B) 1 + 2ab = 3b

(D) 3b + 1 = 2ab(A) a + 2b = 3ab

(C) a - 2b = 3ab

(B) 1 + 2ab = 3b

(D) 3b + 1 = 2ab(A) a + 2b = 3ab

(C) a - 2b = 3ab

(B) 1 + 2ab = 3b

(D) 3b + 1 = 2ab(A) a + 2b = 3ab

(C) a - 2b = 3ab

(B) 1 + 2ab = 3b

(D) 3b + 1 = 2ab(A) a + 2b = 3ab

(C) a - 2b = 3ab

(B) 1 + 2ab = 3b

(D) 3b + 1 = 2ab(A) a + 2b = 3ab

(C) a - 2b = 3ab

(B) 1 + 2ab = 3b

(D) 3b + 1 = 2ab(A) a + 2b = 3ab

(C) a - 2b = 3ab

(B) 1 + 2ab = 3b

(D) 3b + 1 = 2ab

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