Question

4 g H2 reacts with 8 g O2 to form steam. How many moles of gases are there after the
completion of reaction in the vessel?
A) 3
B ) 3.5
C) 2.0
D) 0.5​

Answer 1

Answer:

2.0

Explanation:

Answer 2

Answer:

The unreacted moles of gases = 1.5 moles

The moles of gases are there after the completion of reaction in the vessel is equal to 3.5 moles.

Explanation:

Given, the mass of hydrogen gas = 4g

The number of moles of hydrogen gas = 4/2 = 2 moles

The mass of oxygen gas, = 8/32 = 0.25 moles

The chemical equation:-

2H₂(g)  +  O₂ (g)  $\longrightarrow$   2H₂O (g)

2 moles of hydrogen gas react with 1 mole of oxygen gas and produce 21 moles of water.

Here, we have given 0.25 moles of O₂ react with 2 moles of hydrogen gas. Therefore, oxygen gas acts as limiting reagent because once the amount of oxygen gas finished, reaction will stop.

If  1 mole of oxygen gas react with hydrogen gas = 2moles

Then 0.25 moles of O₂ gas react with H₂ gas = 0.25× 2 = 0.5 moles

Therefore, the amount of H₂ gas reacted = 0.5 moles

The total moles of gases present before reaction = 2 + 0.25 = 2.25

After reaction moles of unreacted gases = 2.25 - (0.5 + 0.25)

                                                                   =  2.25 - 0.75 = 1.5 moles

Amount of water produced = 2moles

The total moles of gases after reaction  = 2 + 1.5 = 3.5 moles

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