Question

4 g of a metalic oxide contain 1.6 g oxygen. The equivalent weight of metal is?

Answer 1

Consider molecular formula of metal oxide as ‘MO’

Oxygen content in metal oxide = 1.6 g

So, Metal content in metal oxide = 4 g - 1.6 g = 2.4 g

Equivalent weight of oxygen = 8

So, equivalent weight of metal = 8 X 2.4/1.6 = 12

Equivalent weight of metal = 12