4 g of an ideal gas (vapour density = 20) is taken in a bulb of 10 dm3 volume, at a temperature of T K. The bulb is placed in a thermostat maintained at a temperature 125ºC more than the initial. To maintain original pressure, 0.8 g of gas has to be removed, then the value of T is
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Explanation:
N1T1=N2T2
4×T÷40=3.2×(T+125)÷40
4T=3.2T+400
T=400÷0.8
T=500
As the Chang in temperature delta T is same in kelvin or in degree Celsius so I've directly taken T2=T+125
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