4 g of cao is formed by decopmposition of caco3 then what is the amount of caco3 taken
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Rxn involved -
CaCO3 → CaO + CO2
moles of CaO formed = 4/ 56 = 0.071
and from the rxn it is clear that 1 mole of CaO is produced by 1 mole of CaCO3
Hence amt of CaCO3 req. = 0.071 × 100 = 7.1 gm
hope this helps
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