4 g of co2 and 22.4 liter of h2 at stp are mixed in a container the total numbet of molecules present in container
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no. of moles of Co2= m/mw
= 4/44
= 1/11
no. molecules of Co2= no. of moles*Avagadro no. (NA=6.623*10^23)
= NA/11
no. moles of H2= 22.4/22.4= 1
no.of molecules= 1*NA =NA
therefore,
Total no. molcules will equal to= NA/11 +NA
12NA/11
= 4/44
= 1/11
no. molecules of Co2= no. of moles*Avagadro no. (NA=6.623*10^23)
= NA/11
no. moles of H2= 22.4/22.4= 1
no.of molecules= 1*NA =NA
therefore,
Total no. molcules will equal to= NA/11 +NA
12NA/11
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