Question

4 g of hydrogen are ignited with 4 g of oxygen
The weight of water formed is -
(1) 0.5g (2)3.59 (3) 4.59 (4)2.59​

Answer 1

We need (i), a stoichiometric equation,

H2(g)+1/2 O2(g)→H2O(l).

we have

 4⋅g/32.O⋅g⋅mol−1=1/8⋅mol dioxygen gas.

And 4⋅g/2.O⋅g⋅mol−1=2⋅mol dihydrogen gas.

Clearly, the dioxygen gas is present in DEFICIENCY, and O2 is the limiting reagent

Given the equation, we can make at

most 1/4⋅mol of water,

i.e. a mass of 1/4⋅mol×18.01⋅g⋅mol−1=4.59⋅g

options 3 is correct

key (-1)= inverse