Question

4 g of methane at 380 torr and 273 c occupies a volume of​

Answer 1

1 torr = 0.00132 atm

380 torr = 0.5 atm

4g of methane have -

No. of moles = Given mass / molar mass

No of moles = 4 / 16 = 1/4 = 0.25 moles

Applying Ideal gas equation

PV = NRT

0.5 × V = 0.25 × 0.0082 × 273

here temp is not given in the question so i took it as standard temp or replace the value of temp in it.

on solving we get

V = 0.11193 or 1.11 lits