4 g of methane at 380 torr and 273c occupies a volume of
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first find number of mole which is 0.25mol (mass/molecular weight) and then by this rule PV=nRT u can find the volume
where P is the pressure in atm
R is gas constant =0.0821
T is temperature in kalvin and n is number of moles
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Answer:22.4 L
Explanation:given mass=4g;actual mass of methane =16 grams; no of moles=1/4; pressure =380/760atm
; Temperature=(273+273)K; V=?
PV=nRT
380/760×V=1/4×0.0821×546
V=1/4×0.0821×546×760/380
V=1/4×44.8×2
V=1/2×44.8
V=22.4L
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