Question

4 g of methane at 380 torr and 273c occupies a volume of​

Answer 1

first find number of mole which is 0.25mol (mass/molecular weight) and then by this rule PV=nRT u can find the volume

where P is the pressure in atm

R is gas constant =0.0821

T is temperature in kalvin and n is number of moles

Answer 2

Answer:22.4 L

Explanation:given mass=4g;actual mass of methane =16 grams; no of moles=1/4; pressure =380/760atm

; Temperature=(273+273)K; V=?

PV=nRT

380/760×V=1/4×0.0821×546

V=1/4×0.0821×546×760/380

V=1/4×44.8×2

V=1/2×44.8

V=22.4L