Question

4 g of NaOH is dissolved in 100ml solution.calculate the normality of the solution.

Answer 1

Hey the molarity comes out to be 1 and we know formula of normality that relate to molarity asN=Mx where X is X factor which represent basicity or acidity so the answer comes out to be 1

Answer 2

The normality of the solution is 1N

Explanation:-

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

$Normality=\frac{\text{no of gram equivalents}}{\text{Volume in L}}$

$Normality=\frac{\text{given mass}}{\text {Equivalent mass}\times {\text{Volume in L}}}$

Equivalent weight is calculated by dividing the molecular weight by n factor.  

${\text{Equivalent weight}}=\frac{\text{Molecular weight}}{n}$

n= acidity for bases , For $NaOH$ , n =1  

$NaOH\rightarrow Na^++OH^{-}$

As  $NaOH$ dissociates to give 1 $OH^-$ and thus it has acidity of 1.

${\text{Equivalent weight}}=\frac{40}{1}=40g$

$Normality=\frac{4g}{40g\times 0.1L}=1N$

Thus Normality will be 1 N

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