Question

4 g of NaOH is present in 100 ml of aqueous solution. The molarity of NaOH in the solution is (Atomic weight of Na = 23)
O 1 M
story
O 2M
O 1.5 M
2.5 M​

Answer 1

Explanation:

no.of moles = mass / molar mass

4/40

no.of moles =10

molarity= no.of Mole/ volume in litre

molarity= 10/100/1000L

answer is 1 M

Answer 2

Answer:

1M

Explanation:

M=n/v(in liters)

Molar mass of NaoH=40

mole= 4/40 =1/10

M=1/10/100/1000=1M