Question

4 g of oxygen reacts with a metal to give 235 g of metal oxide. The equivalent weight of the metal is​

Answer 1

Answer:

Explanation:

First we need to find limiting reactant

O₂ + 2Cu > CuO

32g : 128g

4g   : x

x = (128 * 4) /32      #Using cross multiplication method

x = 16g

Now the same for Oxygen

O₂ + 2Cu > CuO

32g  : 128g

y       : 235

y = (235*32)128     #Using cross multiplication method

y = 58.75g

Oxygen is limiting reactant 58.75 g of Oxygen is needed to completely react with 235g of Cu and we only have 4g.

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We will use mole to mole relation for this

O₂ + 2Cu > CuO

1    :    2     :   1

4g       :         Mr of CuO

4g       :         80g

As 4g of oxygen and Oxygen is limiting reactant so 80g of CuO is produced.