Question

4 g of the metal oxide contains 1.6 g of oxygen then equivalent mass of metal

Answer 1

1.6g oxygen combines with (4-1.6) g metal Therefore 8 g oxygen will combine with. (4-1.6)/1.6 . 8 =. 12 Hence equivalent mass of the metal is 12

Answer 2

Answer: Equivalent mass of metal in metal oxide will be 12 grams.

Explanation: For 4 g of metal oxide (MO), 1.6 grams of oxygen is present. So, the remaining will be metal which is

Mass of metal present = 4 - 1.6 = 2.4 grams

Equivalent mass of oxygen = 8 grams

For calculating equivalent mass of metal in a oxide, we use the formula:

$\text{Equivalent mass of metal}=\frac{\text{Mass of metal}}{\text{Mass of oxygen}}\times \text{Equivalent mass of Oxygen}$

$\text{Equivalent mass of metal}=\frac{2.4g}{1.6g}}\times 8.0g$

Equivalent mass of metal = 12 grams.