Question

4 geometric mean are inserted between sand b if the first and third means are 54 and 24 respectively, find the value of a and b.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Thus a=81 and b=32/3

Step-by-step explanation:

There are 4 GMs between a  and b so b is 5th term and a is I

let r is common ratio

then b=ar^5

I GM= T2=ar=54..................(1)

III Gm =T4=ar^3=24...........................(2)

T4/T2=r²=24/54=4/9

r=2/3

from (1)

a*2/3=54

a=54*3/2=81

b=81*(2/3)^5

=81 * 32/3^5=32/3

Thus a=81 and b=32/3