Question

4. Gibb's free energy (AG) for the given cell will be
Cu(s)/ Cu2+ 11 Agt | Ag(s)
(1.5 x 10 *M) (4.5 x 10-4M)
[Given, Euzticu = 0.34 V, Eating = 0.80 V,
log (1.5) = 0.176, log (4.5) = 0.653]
(1) -59234 J
(2) -64520 J
(3) -72375 J
(4) -92375 J​

Answer 1

Answer:

1st

Explanation:

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