Question

4. Given 15 cot A = 8, find sin A and sec A.​

Answer 1

Answer:

15 cot A =8

cot A= 8/15

cot A = 8/15 = base/height

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Let height be 15x and base be 8x

By Pythagoras Theorem,

(15x)^2 + (8x)^2 = hypotenuse^2

(225 + 64)x^2 = hypotenuse^2

289x^2 = hypotenuse^2

17x = hypotenuse

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Now,

sin A = height/hypotenuse

Sin A = 15/17

AND

sec A = hypotenuse/base

Sec A = 17/8

i hope this will help you

Answer 2

Answer:

$sinA=\frac{15}{17}$

$secA=\frac{17}{8}$

Step-by-step explanation:

$\\15cotA=8\\\\cotA=\frac{8}{15}=\frac{adjacent}{opposite}\\\\hypotenuse=8^{2}+15^{2}\\\\ hypotenuse=17\\\\sinA=\frac{opp}{hyp}\\\\sinA=\frac{15}{17}\\\\secA=\frac{hyp}{adj}\\\\secA=\frac{8}{17}$

I hope it is useful..

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