Question

4. Given 15 cot A = 8, find sin A and sec A. how to solve
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Answer 1

Answer:

Hope it helped........

Answer 2

15 cot A = 8

_______ [GIVEN]

• We have to find sin A and sec A.

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Solution:

=> 15 cot A = 8

=> cot A = $\dfrac{8}{15}$

• We know that cot Ø = $\dfrac{B}{P}$

Here..

• B (base) = 8

• P (perpendicular) = 15

• H (hypotenuse) = ?

» H² = P² + B

=> H² = (15)² + (8)²

=> H² = 225 + 64

=> H² = 289

=> H = √289

=> H = 17

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• sin A = $\dfrac{P}{H}$

=> $\dfrac{15}{17}$

• sec A = $\dfrac{H}{B}$

=> $\dfrac{17}{8}$

_____________ [ANSWER]