Question

4. Given a right circular cylinder (closed at both ends) of radius 3 cm and height 14 cm,

find the following.

(a) The area of its two bases (b) The curved surface area​

Answer 1

Answer:

area of two bases = 28.26 cm square each

CSA = 264 cm square

formula 2pie R H

Answer 2

Given:-

• Radius of the cylinder = 3 cm
• Height of the cylinder = 14 cm

To Find:-

• (a) The area of its two bases.
• (b) The curved surface area of the cylinder.

Solution:-

(a) area of its two bases.

We know,

The base of a cylinder is always circle in shape.

We also know,

• Area of circle = πr² sq.units

Let us calculate the area of one base first.

Area of 1 base = πr²

= Area = 22/7 × (3)²

⇒ Area = 3.14 × 9

⇒ Area = 28.26 cm²

∴ Area of one base = 28.26 cm².

Now,

If area of one base is 28.26 cm²

Area of 2 bases = 28.26 × 2

⇒ Area of 2 bases = 56.52 cm²

∴ The area of two bases of the cylinder is 56.52 cm².

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(b) The curved surface area of the cylinder.

We know,

• Curved Surface Area of the cylinder = 2πrh sq.units.

Hence,

Curved Surface Area = 2 × 22/7 × 3 × 14

⇒ Curved Surface Area = 2 × 22 × 3 × 2

⇒ Curved Surface Area = 264 cm²

∴ The curved surface area of the cylinder is 264 cm².

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Extra Information!!

Some other formulas related to cylinder:-

• Total Surface Area = 2πr(r + h) sq.units

• Volume = πr²h cu.units

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