Question

4. Given M is the mass suspended from a spring of
force constant. k. The dimensional formula for
IM/K] is same as that for
1) frequency
time period
3) velocity
4) wavelength​

Answer 1

Answer:

I think you're question should be :

$\sqrt{M\div k}$

Force = kx

where k = spring contstant

and x = displacement

Dimensional formula of force =

$MLT {}^{ - 2}$

Displacement =

$L$

By equating,

$MLT {}^{ - 2} = kL \\ k \: = MT {}^{ - 2}$

Dimensions of [M/K]^1/2

=

$\frac{M}{MT {}^{ - 2} } = T {}^{2} \\ \sqrt{T {}^{ 2} } = T$

T is the dimension of Time Period.

Therefore, the answer is:

(2)Time Period