4. Given that HCF (306, 657)=9, find LCM (306, 657).
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Answered by
1
Answer:
lcm*hcf=product of numbers
Answered by
6
Answer:
We know
a×b = HCF(a,b)×LCM(a,b)
So,
306×657 = 9×LCM(306,657)
201042 = 9×LCM(306,657)
201042/9 = LCM(306,656)
LCM(306,656) = 22338
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