Math, asked by rohanpandey2100, 9 months ago

4. Given that HCF (306, 657) = 9, find LCM (306, 657).
5. Check whether 6" can end with the digit 0 for any natural number n.​

Answers

Answered by nishanth1729
10

Answer:

4.LCM = 201042/9 = 22338 .

It can be observed that 5 is not in the prime factorisation of 6n. Hence, for any value of n, 6n will not be divisible by 5. Therefore, 6n cannot end with the digit 0 for any natural number n.

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