4. Given that HCF (306,657)=9, find LCM (306, 657).
5. Check whether 6" can end with the digit 0 for any natural number n.
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Answer:
Step-by-step explanation:
Given that HCF = 9 and the numbers are 306 and 657
LCM = ?
We know that LCM × HCF = product of two numbers
⇒LCM × 9 = 306 × 657
⇒LCM = 201042/9 = 22338 .
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