Question

4. Given that HCF (306, 657) = 9, find LCM (306, 657).
5. Check whether 6" can end with the digit() for any natural number n
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Answer 1

Answer:

1. 22338

2. No

Step-by-step explanation:

1. We know that

Product of 2 numbers = LCM × HCF

Given that the 2 numbers are 306 and 657. HCF = 9 we need to find the LCM.

So, 306 × 657 = 9 × LCM

(306×657) /9 = LCM

34 × 657 = LCM

LCM = 22338

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2. No

Factors of 6 = 2×3

It has other factors than 2n and 5m. So, no.