Question

4 gm H2, 32 gm 02, 14 gm N, and 11gm Co, are
taken in a bulb of 500 ml. Which one of these has
maximum active mass?
(1) H2
(2) O2
(3) N₂
(4) CO2
​

Answer 1

Answer:

(1)H2

Explanation:

4 g of H₂ = (4/2) moles of H₂ = 2 moles H₂

32 g of O₂ = (32/32) moles of O₂ = 1 moles of O₂

14 g of N₂ = (14/28) moles of N₂ = 0.5 moles of N₂

11 g of CO₂ = (11/44) moles of CO₂ = 0.25 moles of CO₂

Active mass of H₂ = 4 moles/litre

Active mass of O₂ = 2 moles/litre                  

Active mass of N₂ = 1 mole/litre

Active mass of CO₂ = 0.5 mole/litre

Thus H₂ has the maximum active mass.

Answer 2

Answer:

Here your Answer user.

Explanation:

1) H2

Have maximum active mass.