Question

4 gm H2SO4 dissolved in 250 ml of water. Calculate normality of the solution. (H=1, 0=16, S=32)​

Answer 1

Answer:

0.32 N

Explanation:

volume of water = 250ml

molar weight of H2SO4 =98 g

given weight of H2SO4 = 4g

$moles \: of \: h2so4 = \frac{mass}{molar \: mass}$

$moles = \frac{4}{98}$

$molarity \: (m) = \frac{moles}{volume(l)}$

$molarity \: of \: h2so4 = \frac{ \frac{4}{98} }{0.25} molar$

$molarity \: of \: h2so4 = 0.16 \: molar$

Now,

Normality = Molarity × n factor

n factor of H2SO4 = 2

normality of H2SO4 = 0.16 × 2 N

normality of H2SO4 = 0.32 N

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