Question

4 gm NaOH is present in 100 ml of the solution. What is the normality?

Answer 1

Normality is defined as the number of gram equivalent of solute present in 1000 ml of solution.

$Normality\quad (N)\quad =\quad \frac { Number\quad of\quad gram\quad equivalents\quad of\quad solute }{ Volume\quad of\quad solute }$

Molar mass of NaOH = 40 g/mol.

NaOH is base, therefore n-factor is 1.

$Gram\quad equivalents\quad of\quad solute\quad (NaOH)\quad \quad =\quad \frac { molar\quad mass }{ n\quad -\quad factor } \\ \\=\quad \frac { 40\quad g/mol }{ 1 } \quad \\ \\Gram\quad equivalents\quad of\quad solute\quad =\quad 40\quad g/mol$

4 gm of NaOH is dissolved in 0.1 L solution.

Therefore, normality will be

$Normality\quad (N)\quad =\quad \frac { 4 }{ 40\quad \times \quad 0.1 } \quad =\quad 1\quad N$