4 gram of a metal oxide contains 1.3 gram of oxygen then the equivalent mass of the metal is
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1.6g oxygen combines with (4-1.6) g metal
Therefore 8 g oxygen will combine with.
(4-1.6)/1.6 . 8 =. 12 Hence equivalent mass of the metal is 12
Therefore 8 g oxygen will combine with.
(4-1.6)/1.6 . 8 =. 12 Hence equivalent mass of the metal is 12
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