Question

4 gram of an impure sample of CaCO3 on treatment with excess HCl produces 0.88 grams CO2. find percentage purity of CaCO3.

Answer 1

CaCO3+2HCL→CaCl2+H2O+CO2

44g of CO2→100g of CaCO3

0.88g of CO2→2g of CaCO3

percentage of purity=2/4(100)=50%

Answer 2

Answer:

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