4 gram of hydrogen and 64 gram of Sulphur and 44.8 litre of O2 at STP react and form H2So4 is 49 gram of H2so4. .then % of yield is
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Answer:
Explanation:
Molecular weight of H2SO4 = 98 g/mol
20 g of H2SO4 = 20 /98 ≈ 0.20 moles
1 mole = 6.023 × 10^23 molecules
0.20 moles =12.046 × 10^22 molecules
One molecule of H2SO4 has 4 oxygen atoms,
therefore ;
Number of oxygen atom in 0.2 mole = 4 × 12.046 × 10^22
= 48.184 × 10^22 oxygen atoms
Answered by
0
Answer:
Molecular weight of H2SO4 = 98 g/mol
20 g of H2SO4 = 20 /98 ≈ 0.20 moles
1 mole = 6.023 × 10^23 molecules
0.20 moles =12.046 × 10^22 molecules
One molecule of H2SO4 has 4 oxygen atoms,
therefore ;
Number of oxygen atom in 0.2 mole = 4 × 12.046 × 10^22
= 48.184 × 10^22 oxygen atoms
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