Question

4 gram of silver nitrate is added to form 250 ml of silver nitrate solution.calculate the mass by volume persentage of solution
pls help me out of this ......​

Answer 1

Answer:

Mass by volume % = mass of solute /volume of solution x 100

                                = 4/250  x 100

                               = 1.6%

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Answer 2

Answer:

4.2 g AgNO 3

Explanation:

we  know that a solution's molarity tells you the number of moles of solute present for every  1 L  of solution.

molarity  =  0.100 mol . L − 1

This means that for every  1 L  = 10^3.mL

The solution will contain  

0.100 moles  of silver nitrate,  AgNO 3 . the solute.

Now, notice that your solution has a volume of

250 mL  =10^3.mL/4.

This means that in order to have a molarity of  0.100 mol L − 1 , the solution must contain

0.100 moles AgNO 3 /4  =  0.025 moles AgNO 3

Finally, to convert the number of moles to grams, use the molar mass of silver nitrate

0.025 moles AgNO 3  ⋅x 169.87 g / 1 mole AgNO 3

= 4.2 g

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