Question

4 grams each of pure hydrochloric acid and
caustic soda are together dissolved in water.
What weight of sodium chloride is obtained?
(1) 8 grams
(2) 5.85 grans
(3) 21 grams
(4) 13.57 grams​

Answer 1

Answer:

HCl+NaOH--NaCl+H2O

mole of HCl=4÷36.5=0.109 mole

mole of NaOH = 4÷40=0.1 mole

so, NaOH is Limiting reagent

40g NaOH produces= 58.5g NaCl

4g NaOH produces= 58.5/40×4

=5.85g NaCl

Answer 2

Answer:HCl+NaOH--NaCl+H2O

mole of HCl=4÷36.5=0.109 mole

mole of NaOH = 4÷40=0.1 mole

so, NaOH is Limiting reagent

40g NaOH produces= 58.5g NaCl

4g NaOH produces= 58.5/40×4

=5.85g NaCl

Explanation: