4 grams of hydrogen reacts with some grams of oxygen to make 36 grams of water.figure out how much oxygen must have been used by applying law of conservation of mass
Answers
Answered by
5
Answer:32
Explanation:
36g=xg+4g
Answered by
6
Answer:
Explanation:
The chemical reaction for the formation of water is:
2H₂ + O₂ → 2H₂O
Now,
36 × 1/18 = 2 moles of water
4 g of H₂ × 1/2 = 2 moles of hydrogen
On applying the law of conservation of mass, two moles of hydrogen and 1 mole of oxygen reacts to produce 2 moles of water.
Thus, one mole of oxygen is required to produce 2 moles of water.
1 mole of oxygen × 32 g/mole of water = 32 g of oxygen
Similar questions