4.
) h/(V/V)
The velocity of propagation of sound is
330 ms -1, in air. If the third harmonic of the
fundamental that can be exerted in an open
ended tube is 450 Hz, the length of the tube is
Answers
Answered by
0
Answer:
below this
Explanation:
For closed organ pipe, frequency of the fundamental note
ν
0c
=
4l
v
, where v is velocity of sound and l is the length of the pipe.
For open organ pipe, frequency of the fundamental note
ν
0o
=
2l
v
=2ν
0c
ν
0c
=
2
1
ν
0o
=
2
30
=15 Hz
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