Physics, asked by pm4097, 1 month ago

4.
) h/(V/V)
The velocity of propagation of sound is
330 ms -1, in air. If the third harmonic of the
fundamental that can be exerted in an open
ended tube is 450 Hz, the length of the tube is​

Answers

Answered by dushhitler
0

Answer:

below this

Explanation:

For closed organ pipe, frequency of the fundamental note

ν

0c

=

4l

v

, where v is velocity of sound and l is the length of the pipe.

For open organ pipe, frequency of the fundamental note

ν

0o

=

2l

v

=2ν

0c

ν

0c

=

2

1

ν

0o

=

2

30

=15 Hz

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