Chinese, asked by rahulkumarbedia15, 11 months ago

4 HCL (aq) + MnO2 ->2H2O (L) + MnCL2 (aq)+ CL2(g). how many grams of HCL react with 5.0 g of manganese dioxide

Answers

Answered by preetsingh375

8

1 mol of MnO2 = 55+32 g = 87 g

87 g of MnO2 react with 4 moles of HCl i.e. 4×36.5 g = 146 g of HCl.

∴ 5.0 g of MnO2 will react with HCl = 146/87×5.0 g = 8.40 g.

Answered by clairchitvankaur

0

Answer:

8.4 grams

Explanation:

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