Math, asked by shashirathod654, 2 months ago

4 Helical spring is loaded with a force of 400 New ton and it is compressed by 18 mm. What would be the load required to compress it to 6 mm?

Given force

Deflection

= 400 Newton

= 18 mm

Answers

Answered by madhan6070

0

Answer:

I don't know

Step-by-step explanation:

what a question wonderful great

Answered by navaneethpoojary128

0

Answer:

Spring stiffness=Force/Compressed length

400/18(N/mm)

22.22N/mm

Load required to compress the spring by 6mm

Spring stiffness×deflection

22.22×6

Load required=133.32

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