Question

4.How many 176 Ω resistors (in parallel)are required to carry 5A on a 220 V line?​

Answer 1

Solution:

Let us assume number of resistors are x

As we know that

x number of resistors are connected in parallel

1/Eq. resistance = x/176

By cross multiplying

→ R = 176/x

Now , using ohm's law

V = I × R

Where

• V → Voltage = 220V
• I → Current = 5 A
• R → Resistors = x = ?

Substituting the values we have

→ 220 = 5 × x

→ 220/5 = x

→ x = 44

Hence , number of resistors = 44.