Question

4. How many numbers are there between
99 and 1000 such that the digit 8
occupies the units place?
[UPSC CSAT 2017]
(a) 64 (b) 80
(C) 90 (d) 104​

Answer 1

Answer:

Step-by-step explanation:

This gives us 9∗9=819∗9=81 numbers with 88 in hundered's place. Hundred's place can be filled up with any digit from 1–9,1–9,barring 88, i.e. 8 such digits. Units place can be filled up with any digit from 00–9,–9, barring 88 i.e. 9 such digits. This gives us 99∗8=72∗8=72numbers, with 88 in tens place.

Answer 2

Answer:

answer is options c =90