4. How many numbers of three digits are divisible by 9?
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Answered by
1
Answer:
where first term = 108, last term = 999, common difference = d = 9, n is to be found. n = 100. Therefore, there are 100 three-digit numbers divisible by 9.
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Answered by
1
Answer:
Step-by-step explanation:
The series for this is as :
108, 117, 126,.................999
a = 108, d= 9, an= 999, n=?
an = a+(n-1)d
999= 108+(n-1)9
999 - 108= 9(n-1)
891= 9(n-1)
891/9= n-1
99= n-1
n= 99+1
n= 100
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