Question

4. How many numbers of three digits are divisible by 9?​

Answer 1

Answer:

where first term = 108, last term = 999, common difference = d = 9, n is to be found. n = 100. Therefore, there are 100 three-digit numbers divisible by 9.

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Answer 2

Answer:

Step-by-step explanation:

The series for this is as :

108, 117, 126,.................999

a = 108, d= 9, an= 999, n=?

an = a+(n-1)d

999= 108+(n-1)9

999 - 108= 9(n-1)

891= 9(n-1)

891/9= n-1

99= n-1

n= 99+1

n= 100

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