Question

4. How many odd 4-digit positive
integers that are multiples of 5 can
be formed without using the digit
3?​

Answer 1

The answer is 648 integers

Step-by-step explanation:

I would choose 'A' for it.

Since the number is odd number and multiple of 5, we can fix digit '5' as the 4th digit.

Remaining 1st digit can be any 8 numbers other than '0' and '3', 2nd digit can be and 9 numbers other than '3' and 3rd digit can be any '9' numbers other than '3', making possibilities to be- 8X9X9X1= 648

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