Question

4. How many three digit numbers are divisible by 5​

Answer 1

Answer:

180

Step-by-step explanation:

The three digit number are

100 , 101, 102, 103......999

The three digit natural numbers which are divisible by 5 are

100, 105, 110, .......995

Here,

a = 100

d = 5

tn = 995

We have to find n = ?

Formula : tn = a + (n-1)d

Therefore ,

tn = a + (n-1)d

995 = 100+(n-1)5

995-100 = (n-1)5

895 = (n-1)5

895/5 = (n-1)

n-1 = 179

n = 179+1

n = 180

$\boxed{</em></strong><strong><em>A</em></strong><strong><em>ns \: = 180}$

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