4. How to calculate the total number of byes, if total number of team is odd ?
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Answered by
6
Teams in upper half by formula N+1/2
Teams in lower half by formula N-1/2
Byes in upper half by formula N-1/2
Byes in lower half by formula N+1/2
Teams in each quarter is total teams divided by 4
{19/4} we have 4 as our quotient so
1st Q = 4+1
2nd Q = 4+1
3rd Q = 4+1
4th Q = 4
BYES ARE ALWAYS DISTRIBUTED FROM THE LAST TO FIRST
AS IN CASE OF UPPER HALF BYE WILL BE GIVEN AS FOLLOWS
LAST - FIRST - SECOND LAST -SECOND AND SO ON…
THEN SAME FOR SECOND HALF
Hopefully this helps you
Teams in lower half by formula N-1/2
Byes in upper half by formula N-1/2
Byes in lower half by formula N+1/2
Teams in each quarter is total teams divided by 4
{19/4} we have 4 as our quotient so
1st Q = 4+1
2nd Q = 4+1
3rd Q = 4+1
4th Q = 4
BYES ARE ALWAYS DISTRIBUTED FROM THE LAST TO FIRST
AS IN CASE OF UPPER HALF BYE WILL BE GIVEN AS FOLLOWS
LAST - FIRST - SECOND LAST -SECOND AND SO ON…
THEN SAME FOR SECOND HALF
Hopefully this helps you
Answered by
0
Answer:
Answer will come also a odd number.
Explanation:
It is very easy. Suppose you have to draw a fixture of 11 teams on knock put basis.
Here we go with the formula:
First divide the teams into two halves, i.e upper half & lower half, then:
No. Of teams in the upper half= N+1/2,
i.e 11+1/2 =12/2 =6 teams in upper half
Then lower half= N-1/2,
= 11–1/2 = 10/2=5 teams in lower half
Therefore total No. Of byes:
Total no. of teams = 11
Next highest power of two =( 2)^4 =16
(Formula= 2^n - N) where N is the no. Of teams.
So the no. Of byes to be placed is
16–11 = 5 byes.
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